If a leak lasts 3 hours at 1.5 kg/s, spilled mass would be:

If a leak lasts 3 hours at 1.5 kg/s, spilled mass would be:

• A. 10800 kg
• B. 16200 kg
• C. 9000 kg
• D. 13500 kg

Answer: (B)

Mass spilled equals the flow rate times the duration, with consistent units. The leak rate is 1.5 kilograms per second, and the duration is 3 hours. Convert 3 hours to seconds: 3 × 3600 = 10800 seconds. Multiply: 1.5 kg/s × 10800 s = 16200 kg. So the spilled mass is 16,200 kilograms. (As a cross-check, you can convert the rate to kilograms per hour: 1.5 kg/s × 3600 s/hour = 5400 kg/hour, then 5400 × 3 = 16200 kg.)

Mass spilled equals the flow rate times the duration, with consistent units. The leak rate is 1.5 kilograms per second, and the duration is 3 hours. Convert 3 hours to seconds: 3 × 3600 = 10800 seconds. Multiply: 1.5 kg/s × 10800 s = 16200 kg. So the spilled mass is 16,200 kilograms. (As a cross-check, you can convert the rate to kilograms per hour: 1.5 kg/s × 3600 s/hour = 5400 kg/hour, then 5400 × 3 = 16200 kg.)